The Hypergeometric Probability
Output Sample of MD2002
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Subjects
Q1. A set of 13 bridge card. Find the chance to have 7 spades
A1. Answer
  • (1) H(N, n, k, x)=C(k, x)*(N-k, n-x)/C(N, n)
  • (2) Population = N = 52
  • (3) Sample = k = 13
  • (4) Take = n = 13
  • (5) Expectation = x = 7. H(x=7)=C(13,7)*(39,6)/(52,13) = ?
  • (6) Find H(x=7) by using MD2002 19 30
Example : find probability that one hand 13 cards without spade
  • N = 52, n = 13.
  • Since expectation x = 0 and hence k = 13.
  • Hence probability H(x=0) is C(13,0)*C(39,13)/(52,13) = 0.0128
Q2. A set of 5 bridge card. Find the chance to have 4 A
A2. Answer
  • (1) H(x)=C(n, x)*(N-k, k-x)/C(N n)
  • (2) Population = N = 52
  • (3) Sample = k = 4
  • (4) Take = n = 5
  • (5) Expectation = x = 4. H(x=4)=C(5;4)*(48;1)/(52;5) = ?
  • (6) Find H(x=4) using MD2002 19 30
  • (7) Note : Should k be equal 5 ? Give your comments
Reference
  • MD2002 program 19 30
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