Figure 31 : Petals of R=sin(3.1*A)
Product no. Program ABG 01 08
Q1. Find number of petals of r=sin(3.1*A) ?
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* Let 3.1=31/10
* Then r=sin(3.1*A)=sin(31*A/10)
* That is p=31 and q=10 and M=1 in r=sin(p*A/q)
* Since p is odd, q is even and M is odd
* Hence it has 62 petals and cycle domain is 20*pi
Q2. Can we get a rule from Q1 ?
A2. Yes
- If p=odd, q=even and M=odd
- The number petals is 2*p
- Cycle domain is 2*q*pi