Mathematics Dictionary
Dr. K. G. Shih
Demoivre's Theory
Subjects
Symbol Defintion
Example : Sqr(x^2) = Square root of x
AL 18 00 |
- Outlines
AL 18 01 |
- Imaginary number and complex numbers
AL 18 02 |
- Solve X^3 - 1 = 0 geometrically
AL 18 03 |
- Solve X^4 - 1 = 0 geometrically
AL 18 04 |
- Solve X^5 - 1 = 0 geometrically
AL 18 05 |
- Solve x^3 + 1 = 0 by construction
AL 18 06 |
- Solve x^4 + 1 = 0 by construction
AL 18 07 |
- Solve x^5 + 1 = 0 by construction
AL 18 08 |
- Solve x^3 + x^2 + x + 1 = 0
AL 18 09 |
- Solve x^4 + x^3 + x^2 + x + 1 = 0 by construction
AL 18 10 |
- Solve x^4 - x^3 + x^2 - x + 1 = 0 by construction
AL 18 11 |
- Solve x^4 - i = 0 by construction
AL 18 12 |
- Solve x^4 + i = 0
AL 18 13 |
-
AL 18 14 |
- Quiz for complex numbersNew
AL 18 15 |
- Answer to quiz
AL 18 16 |
- Reference
AL 18 17 |
- Summary and formula
Answers
AL 18 01. Imaginary number and complex numbers
Outlines
Complex number expression
z = a + b*i is complex number.
a is sames x in rectangular coordinate
b is sames y in rectangular coordinate
What is conjugate complex number ?
z1 = a + b*i is conjugate of z2 = a - b*i
Properties 1 : z1 + z2 = real
Properties 2 : z1*z2 = real = a^2 + b^2
More defintion and examples
Subject |
Complex number.
Apllication of DeMoivre Theory
Solve x^n - 1 = 0
Draw a large unit circle. On circle draw n point A, B, C, ...
Angles between A, B, C, ... are Ang = 360/n
1st angle AOX = 0/n = 0
2nd angle BOX = 1*Ang + 1st angle
3rd angle COX = 2*Ang + 1st angle
...
Solve x^n + 1 = 0
Draw a large unit circle. On circle draw n point A, B, C, ...
Angles between A, B, C, ... are Ang = 360/n
1st angle AOX = 180/n
2nd angle BOX = 1*Ang + 1st angle
3rd angle COX = 2*Ang + 1st angle
...
Solve x^n - i = 0
Draw a large unit circle. On circle draw n point A, B, C, ...
Angles between A, B, C, ... are Ang = 360/n
1st angle AOX = 90/n = 0
2nd angle BOX = 1*Ang + 1st angle
3rd angle COX = 2*Ang + 1st angle
...
Solve x^n + i = 0
Draw a large unit circle. On circle draw n point A, B, C, ...
Angles between A, B, C, ... are Ang = 360/n
1st angle AOX = 270/n = 0
2nd angle BOX = 1*Ang + 1st angle
3rd angle COX = 2*Ang + 1st angle
...
Go to Begin
AL 18 02. Solve X^3 - 1 = 0 geometrically
Method
1. Draw coordiante OX and OY
2. Draw unit circle with center at O
3. Draw 3 points A, B and C on unit circle
4. Angles between OA, OB and OC are 360/3 = 120
Angle AOX = 0
Angle BOX = 1*120 = 120
Angle COX = 2*120 = 240
Solution : The roots are R0, R1 and R2
Find R0 using complex coordiante at A : R0 = x + y*i
At A : x = 1 and y = 0
Hence R0 = 1 + 0*i = 1
Find R1 using complex coordiante at B : R1 = x + y*i
At B : x = -0.5 and y = 0.866 by measurement
Hence R1 = -0.5 + 0.866*i
Find R2 using complex coordiante at C : R2 = x + y*i
At C : x = -0.5 and y = -0.866 by measurement
Hence R2 = -0.5 - 0.866*i
Note
Note 1 : R2 is conjugate of R1, Hence we can get R2 using R1
Note 2 : Using right angle triangle wirh 30 degrees, we can find R1 = -1/2 + i*Sqr(3)/2
Go to Begin
AL 18 03. Solve X^4 - 1 = 0 geometrically
Method
1. Draw coordiante OX and OY
2. Draw unit circle with center at O
3. Draw 3 points A, B C and D on unit circle
4. Angles between OA, OB, OC and OD are 360/4 = 90
Angle AOX = 0
Angle BOX = 1*90 = 90
Angle COX = 2*90 = 180
Angle DOX = 3*90 = 270
Solution : The roots are R0, R1, R3 and R4
Find R0 using complex coordiante at A : R0 = x + y*i
At A : x = 1 and y = 0
Hence R0 = 1 + 0*i = 1
Find R1 using complex coordiante at B : R1 = x + y*i
At B : x = 0.0 and y = 1 by measurement
Hence R1 = 0 + 1*i = i
Find R2 using complex coordiante at C : R2 = x + y*i
At C : x = -1 and y = 0 by measurement
Hence R2 = -1 - 0*i = -1
Find R3 using complex coordiante at D : R3 = x + y*i
At D : x = 0 and y = -1 by measurement
Hence R3 = 0 - 1*i = -i
Note
Note 1 : R1 is conjugate of R3 and R1*R3 = -i^2 = 1
Note 2 : Diagram in AL 18 04)
Go to Begin
Q04.Solve X^5 - 1 = 0 geometrically
Method
1. Draw coordiante OX and OY
2. Draw unit circle with center at O
3. Draw 3 points A, B C, D and E on unit circle
4. Angles between OA, OB, OC, OD and OE are 360/5 = 72
Angle AOX = 0
Angle BOX = 1*72 = 072
Angle COX = 2*72 = 144
Angle DOX = 3*72 = 216
Angle EOX = 4*72 = 288
Solution : The roots are R0, R1, R3 and R4
Find R0 using complex coordiante at A : R0 = x + y*i
At A : x = 1 and y = 0
Hence R0 = 1 + 0*i = 1
Find R1 using complex coordiante at B : R1 = x + y*i
At B : x = 0.309 and y = 0.951 by measurement
Hence R1 = 0.309 + 0.951*i
Find R2 using complex coordiante at C : R2 = x + y*i
At C : x = -0.309 and y = 0.951 by measurement
Hence R2 = -0.309 + 0.951*i
Find R3 using complex coordiante at D : R3 = x + y*i
At D : x = -0.309 and y = -0.951 by measurement
Hence R3 = -0.309 - 0.951*i
Find R4 using complex coordiante at E : R3 = x + y*i
At D : x = 0.309 and y = -0.951 by measurement
Hence R3 = 0.309 - 0.951*i
Diagram
Subject |
21 01 : Diagrams.
Enter 21 01
Open application program
Select run at current location (No download)
Select yes to run
Click 01 in upper box
click 09 in lower box : Solve x^n - 1 = 0
Give data : 5 (n = 5)
On the diagram : Five points on circle are the solutions
Note
Note 1 : R1 is conjugate of R4 and R1*R4 = 1
Note 2 : R2 is conjugate of R3 and R2*R3 = 1
Go to Begin
AL 18 05. Solve x^3 + 1 = 0
Method
1. Draw coordiante OX and OY
2. Draw unit circle with center at O
3. Draw 3 points A, B and C on unit circle
4. Angles between OA, OB and OC are 360/3 = 120
5. Angle AOX = 180/3 = 60
Angle AOX = 60
Angle BOX = 60 + 1*120 = 180
Angle COX = 60 + 2*120 = 300
Solution : The roots are R0, R1 and R2
Find R0 using complex coordiante at A : R0 = x + y*i
At A : x = 0.5 and y = 0.866
Hence R0 = 0.5 + 0.866
Find R1 using complex coordiante at B : R1 = x + y*i
At B : x = -1 and y = 0 by measurement
Hence R1 = -1 + 0*i = -1
Find R2 using complex coordiante at C : R2 = x + y*i
At C : x = 0.5 and y = -0.866 by measurement
Hence R2 = 0.5 - 0.866*i
Notes
1. R2 is conjugate of R1, Hence we can get R2 using R1
2. Using right angle triangle wirh 30 degrees, we can find R0 = 1/2 + i*Sqr(3)/2
Example : Solve x^2 - x + 1 = 0
Method 1 : Using above method
R0 and R2 are solutions
Since x^2 + x + 1 is a factor of (x^3 - 1).
Method 2 : Using quadratic formula
x1 = (1 + Sqr(1^2 - 4*1*1))/2 = (1 + i*Sqr(3))/2.
x2 = (1 - Sqr(1^2 - 4*1*1))/2 = (1 - i*Sqr(3))/2.
Go to Begin
AL 18 06. Solve x^4 + 1 = 0.
Method
1. Draw coordiante OX and OY
2. Draw unit circle with center at O
3. Draw 3 points A, B C and D on unit circle
4. Angles between OA, OB, OC and OD are 360/4 = 90
5. Angle AOX = 180/4 = 45
Angle AOX = 45
Angle BOX = 45 + 1*90 = 135
Angle COX = 45 + 2*90 = 225
Angle DOX = 45 + 3*90 = 315
Solution : The roots are R0, R1, R3 and R4
Find R0 using complex coordiante at A : R0 = x + y*i
At A : x = y = Sqr(2)/2
Hence R0 = Sqr(2)/2 + i*Sqr(2)/2
Find R1 using complex coordiante at B : R1 = x + y*i
At B : x = -Sqr(2)/2 and y = Sqr(2)/2 by measurement
Hence R1 = -Sqr(2)/2 + i*Sqr(2)/2
Find R2 using complex coordiante at C : R2 = x + y*i
At C : x = -Sqr(2)/2 and y = -Sqr(2)/2 by measurement
Hence R2 = -Sqr(2)/2 - i*Sqr(2)/2
Find R3 using complex coordiante at D : R3 = x + y*i
At D : x = Sqr(2)/2 and y = -Sqr(2)/2 by measurement
Hence R3 = Sqr(2)/2 - i*Sqr(2)/2
Go to Begin
AL 18 07. Solve x^5 + 1 = 0
Method
1. Draw coordiante OX and OY
2. Draw unit circle with center at O
3. Draw 3 points A, B C, D and E on unit circle
4. Angles between OA, OB, OC, OD and OE are 360/5 = 72
Angle AOX = 180/5
Angle AOX = 36
Angle BOX = 36 + 1*72 = 108
Angle COX = 36 + 2*72 = 180
Angle DOX = 36 + 3*72 = 252
Angle EOX = 36 + 4*72 = 324
Solution : The roots are R0, R1, R3 and R4
Find R0 using complex coordiante at A : R0 = x + y*i
At A : x = 0.809 and y = 0.588
Hence R0 = 0.809 + 0.588*i
Find R1 using complex coordiante at B : R1 = x + y*i
At B : x = 0.-809 and y = 0.588 by measurement
Hence R1 = -0.809 + 0.588*i
Find R2 using complex coordiante at C : R2 = x + y*i
At C : x = -1 and y = 0 by measurement
Hence R2 = -1
Find R3 using complex coordiante at D : R3 = x + y*i
At D : x = -0.809 and y = -0.588 by measurement
Hence R3 = -0.809 - 0.588*i
Find R4 using complex coordiante at E : R3 = x + y*i
At D : x = 0.809 and y = -0.588 by measurement
Hence R3 = 0.809 - 0.588*i
Notes
Note 1 : R0 is conjugate of R4 and R0*R4 = 1
Note 2 : R1 is conjugate of R3 and R1*R3 = 1
Go to Begin
AL 18 08. Solve x^3 + x^2 + x + 1 = 0
Solution
Since x^4 - 1 = (x - 1)*(x^3 + x^2 + x + 1) = 0
Hence x^3 + x^2 + x + 1 = 0 has 3 roots in x^4 - 1 = 0
Hence x = -1, x = i and x = -i are the solutions of x^3 + x^2 + x + 1 = 0
Prove that x = i is solution of x^3 + x^2 + x + 1 = 0
Since i^3 + i^2 + i + 1 = (-i) + (-1) + i + 1 = 0
Hence x = i is a solution
Go to Begin
AL 18 09. Solve x^4 + x^3 + x^2 + x + 1 = 0 by construction
Using solution of x^5 - 1 = 0 in AL 18 05
Since (x^5 - 1) = (x - 1)*(x^4 + x^3 + x^2 + x + 1).
Hence we can use the solutions of x^5 - 1 = 0 in AL18 05.
Go to Begin
AL 18 10. Solve x^4 - x^3 + x^2 - x + 1 = 0
Using solution of x^5 + 1 = 0 in AL 18 07
Since (x^5 + 1) = (x + 1)*(x^4 - x^3 + x^2 - x + 1).
Hence we can use the solutions of x^5 + 1 = 0 in AL18 07.
Go to Begin
AL 18 11. Solve x^4 - i = 0
Construction
Draw unit circle. Draw 4 points A,B,C,D on circle
Angles between points = 360/4 and 1st angle is 90/4 = 22.5
Draw angle AOX = 22.5 degrees
Draw angle BOX = 1*90 + 22.5 = 115.5degrees
Draw angle COX = 2*90 + 22.5 = 205.5
Draw angle DOX = 3*90 + 22.5 = 295.5
Solution : The four roots can be obtained by measurements
R1 = Complex coordinate of A = a + p*i
a = 0.924
p = 0.383
R2 = Complex coordinate of A = b + q*i
b = -0.431
q = +0.903
R3 = Complex coordinate of A = c + r*i
c = -0.903
r = -0.431
R4 = Complex coordinate of A = d + s*i
d = +0.431
s = -0.267
Prove that 0.924 + 0.383*i is a solution of x^4 - i = 0
x^4 = (0.924 + 0.383*i)^4
= (0.924^4)+ 4*(0.924^3)*(0.383)*i+ 6*(0.924^2)*(0.383^2)*(i^2)
+ (0.924)*(0.383^3)*(i^3) + (0.383^4)*(i^4)
= 0.729 + (4*0.789*0.383)*i + (6*0.854*0.147)*(1) + ...
= 0.00 + 0.99*i
Hence it is a solution
Exercise
Draw a large unit circle
Find a,b,c,d and p,q,r,s by measurement
Go to Begin
AL 18 12. Solve x^4 + i = 0
Construction
Draw unit circle. Draw 4 points A,B,C,D on circle
Angles between points = 360/4 and 1st angle is 270/4 = 67.5
Draw angle AOX = 22.5 degrees
Draw angle BOX = 1*90 + 67.5 = 157.5degrees
Draw angle COX = 2*90 + 67.5 = 247.5
Draw angle DOX = 3*90 + 67.5 = 337.5
Solution : The four roots can be obtained by measurements
R1 = Complex coordinate of A = a + p*i
a = 0.3826
p = 0.9239
R2 = Complex coordinate of A = b + q*i
b = -
q = +
R3 = Complex coordinate of A = c + r*i
c = -
r = -
R4 = Complex coordinate of A = d + s*i
d = +
s = -
Prove that 0.3826 + 0.9293*i is a solution of x^4 + i = 0
(0.3826 + 0.9293*i)
= 0.00 - 0.99*i
Hence it is a solution
Go to Begin
AL 18 13.
Go to Begin
AL 18 14. Quiz
1. Rationalize z = 1/(1/2 - i*Sqr(3)/2)
2. What are conjugate complex numbers ?
3. Solve x^2 - i = 0 by construction
4. Solve x^3 - i = 0 by construction
Go to Begin
AL 18 15. Answer to Quiz
1. Rationalize z = 1/(1/2 - i*Sqr(3)/2).
Multiply numeritor and denominator by (1/2 + i*Sqr(3)/2).
z = (1/2+i*Sqr(3)/2)/((1/2-i*Sqr(3)/2)*(1/2+i*Sqr(3)/2)).
z = (1/2+i*Sqr(3)/2)/(1/4 - (i^2)*3/4).
z = (1/2+i*Sqr(3)/2)/(1/4 +3/4).
z = (1/2-i*Sqr(3)/2).
2. What are conjugate complex numbers.
Sum of complex numbers = real.
Product of complex numbers = real.
3. Solve x^2 - i = 0 by construction
Draw large unit circle
Draw two point A and B on circle
Angle between A and B is 360/2 = 180
Let angle AOX = 90/2 = 45
Let angle BOX = 180 + 45 = 225
Hence 1st root = a + p*i = +0.7071 + 0.7071*i
Hence 2nd root = b + q*i = -0.7071 - 0.7071*i
4. Solve x^2 + i = 0 by construction
Draw large unit circle
Draw two point A and B on circle
Angle between A and B is 360/2 = 180
Let angle AOX = 270/2 = 135
Let angle BOX = 180 + 135 = 315
Hence 1st root = a + p*i = -0.7071 + 0.7071*i
Hence 2nd root = b + q*i = +0.7071 - 0.7071*i
Go to Begin
AL 18 16. Reference
On PC computer : Use MD2002 Chapter 8.
On internat :
Complex Number
Go to Begin
AL 18 17. Formula
1. Factors
x^2 - 1 = (x - 1)*(x + 1)
x^4 - 1 = (x - 1)*(x + 1)*(x^2 + 1) = x^3 + x^2 + x + 1
x^3 + 1 = (x + 1)*(x^2 - x + 1)
x^5 + 1 = (x + 1)*(x^4 - x^3 + x^2 - x + 1)
x^7 + 1 = (x + 1)*(x^6 - x^5 + x^4 - x^3 + x^2 - x + 1)
x^3 - 1 = (x - 1)*(x^2 + x + 1)
x^5 - 1 = (x - 1)*(x^4 + x^3 + x^2 + x + 1)
x^7 - 1 = (x - 1)*(x^6 ) x^5 + x^4 + x^3 + x^2 + x + 1)
Go to Begin
AL 18 00. Summary and formula
1. Imaginary number and complex number
Imaginary number i = Sqr(-1)
i^2 = -1
i^3 = -i
i^4 = +1
i^5 = +i
Complex Number
Rectangular form z = x + i*y.
Solve x^n - 1 = 0
n is positive integer
The solutions can be used for x^(n-1) + x^(n-2) + .... + x + 1 = 0
Solve x^n + 1 = 0
n is positive integer
The solutions can be used for x^(n-1) - x^(n-2) + .... - x + 1 = 0 if n is even
2. Solve x^n - 1 = 0 by construction
Draw large unit circle
Draw n points A, B, C, .... on circle
Angles between points are Ang = 360/n
1st angle AOX = 0/n
2nd angle BOX = 1*Ang + 1st angle
....
3. Solve x^n + 1 = 0
Same as above but 1st angle = 180/n
3. Solve x^n + i = 0
Same as above but 1st angle = 90/n
Go to Begin
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