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Figure 219 : y = (2*x^2)/(x^2 - 1)

    y = (2*x^2)/(x^2 - 1)


  • Q01 | - Diagram : y = (2*x^2)/(x^2 - 1)
  • Q02 | - Describe ther curve of y = (2*x^2)/(x^2 - 1)
  • Q03 | - Curve and y' and y"
  • Q04 | - Curve and y"
  • Q05 | - Graphic solution is easy and clear


    Q01. Diagram


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    Q02. Cubic function has 3 zeros

    Find y-intercept
    • When x = 0 and y = 0
    Find asymptote
    • Horizontal asymptote : When x = infinite and y = 2
    • Vertical asymptotes :
      • x = +1 and y = infinte
      • x = -1 and y = infinite
    Signs of y, y' and y"
    • When x < -1
      • y is positive and curve is in 2nd quadrant and y > 2
      • x = -infinite and y = 2
      • x = -1 and y = +infinite
      • Hence the curve is increasing from (-infinite, 2) to (-1, infinite)
      • Hence the curve is concave upward
      • Hence y' is positive and y" is positive
    • When x between -1 and 0
      • x = -1 and y = -infinite
      • x = 0 and y = 0
      • Hence curve is increasing from (-1, -infinite) to (0,0)
      • Hence curve is concave downward
      • Hence y' is positive and y" is negative
    • When x between 0 and 1
      • x = 0 and y = 0
      • x = 1 and y = -infinite
      • Hence curve is decreasing from (0, 0) tp(1, -infinite)
      • Hence curve is concave downward
      • Hence y' is negative and y" is negative
    • When x > 1
      • y is positive and curve is in 1st quadrant and y >
      • x = 1 and y = infinite
      • x = infinite and y = 2
      • Hence the curve is decreasing from (1, infinite) to (infinite, 2)
      • Hence the curve is concave upward
      • Hence y' is negative and y" is positive

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    Q03. Find y'

    First derivative y'
    Curve and y'

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    Q04. Find y"

    Second derivative y"
    • y" =
    Curve and y"

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    Q05. Discussion

    Graphic solution
    • The graphic solution is clear determine the signs of y, y' and y"
    • The maximum and minimum points can only be estimated

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