Mathematics Dictionary
Dr. K. G. Shih
Figure 065 : Names of quarilaterals
Q01 |
- Diagram : Names of quarilaterals
Q02 |
- Properties of parallelogram
Q03 |
- Square and rhombus
Q04 |
- Recangle
Q05 |
- Find area
Q06 |
- Symmetrical axese of regular polygon
Q01. Diagram
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Q02. Properties of parallelogram
Parallelogram
1. Opssosite sides are parallel
2. Opssosite sides are parallel and equal
3. Opposite angles are equal
4. Diagonals bisect each other
5. Two neighbour angles are supplemintary
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Q03. Square and rhombus
Squre
1. Four sides are equal
2. Opssosite sides are parallel and equal
3. Each internal angle = 90 degrees
4. Diagonals bisect each other and perpendicular each other
5. It has 4 symmetrical axis
Two Side to side perpendicular lines
Two Veterx to vertex lines
Rhombus
1. Four sides are equal
2. Opssosite sides are parallel and equal
3. Opposite angles are equal
4. Each internal angle = 90 degrees
5. Diagonals bisect each other but not perpendicular each other
6. It has 2 symmetrical axis
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Q04. Rectangle
1. Two opposite sides are equal
2. Opssosite sides are parallel and equal
3. Each internal angle = 90 degrees
4. Diagonals bisect each other but not perpendicular each other
5. It has 2 symmetrical axis
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Q05. Symmetrical axises of regular polygon
Area of square
Let side be a
Area = a^2
Area of rectangle
Let side be a and b
Area = a*b
Area of rhombus : Use cosine law
Let side be a and one angle be U
Let diagonals be b and c
Use cosine law
b^2 = a^2 + a^2 - 2*a*a*cos(U) = 2*(a^2)*(1 - cos(U))
c^2 = a^2 + a^2 - 2*a*a*cos(pi - U) = = 2*(a^2)*(1 + cos(U))
Area
= b*c
= 2*(a^2)*Sqr((1 - cos(U))*(1 + cos(U)))
= 2*(a^2)*Sqr((1 - cos(U)^2))
= 2*(a^2)*Sqr(sin(U)^2)
= 2*(a^2)*sin(U)
Area of rhombus : Use 4 right angle triangle
Let side be a and one angle be U
Right angle triangle
Hypothese = a
Angle 1 = U/2 and side1 = a*sin(U/2)
Angle 2 = (pi - U)/2 and side 2 = a*sin(pi/2 - U/2) = a*cos(U/2)
area = (side 1)*(side 2) = (a^2)*sin(U/2)*cos(U/2) = (a^2)*sin(U)/2
Area of rhombus = 4*(area of triangle) = 2*(a^2)*sin(U)
Area of parallelogram
Let sides AB = u and AC = v
Height h = u*sin(BAC)
Area = h*v/2 = u*v*sin(A)/2
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Q06. Symmetrical axises of regular polygon
Example 1 : Equal size triangle has 3 symmetrical axese
From vertex draw line perpendicular to the oppsite side
Hence we can draw 3 symmetrical axese
Example 2 : Square has 4 symmetrical axese
Vertex to vertex
From vertex draw line perpendicular to the oppsite vertex
Hence we can draw 2 symmetrical axese
Side to side
From mid point of one side draw line to mid point of opposite side
Hence we can draw another 2 symmetrical axese
Square can have total 4 symmetrical axese
Example 3
1. Regular Pentagon has 5 symmetrical axese
2. Regular Pentagon has 6 symmetrical axese
Defintion of polygon
Regular polygons : Their sizes are equal.
Number of symmetrical axes of regular polygon equal to number of sides
Each internal angle is (n*pi - 2*pi)/n
Examples
Equilateral triangle : Each angle = (3*pi - pi)/3 = 60 degrees
Square : Each angle = (4*pi - 2*pi)/4 = 90 degrees
Pentagon : Each angle = (5*pi - 2*pi)/5 = 108 degrees
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