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Mathematics Dictionary
Dr. K. G. Shih

Quadrilateral and Parallelogram
Subjects


  • GE 06 00 | - Outlines
  • GE 06 01 | - Introduction diagrams
  • GE 06 02 | - Square : Properties
  • GE 06 03 | - Rectangle : Properties
  • GE 06 04 | - Parallelogram : Properties
  • GE 06 05 | - Rhombus : Properties
  • GE 06 06 | - Change quadrilateral to equal area of trinagle
  • GE 06 07 | -
  • GE 06 08 | -
  • GE 06 09 | -
  • GE 06 10 | - Change square to equal area triangle
  • GE 06 Q11 | - Change quadrilateral to equal area triangle
  • GE 06 12 | -

  • Answers


    GE 06 01. Introduction

    Diagrams
    Properties of quadrilateral
    • It has 4 sides and 4 angles
    • Sum of internal angles = 2*pi
    • Sum of external angles = 2*pi
    • Join the mid points of 4 sides forming a parallelogram
    • If 4 vertices A,B,C,D are on same circle
      • It is called four points being concylic
      • Then sum of the opposite angles = 180 degrees

    Go to Begin

    GE 06 02. Square : Properties

    • Four sides are equal and each side is a
    • The area is a^2
    • Each internal angle is 90 degrees
    • Diagonals bisect each other equally
    • Diagonals are perpendicular each other
    • Diagonals bisect the opposite angles
    • It has four symmetrical axese
      • Two are the diagonals
      • Two are the bisectors of opposite sides
    • Opposite sides are parallel

    Go to Begin

    GE 06 03. Rectangle : Properties

    • Opposite sides are equal and the sides are a, b, a, b
    • The area is a*b
    • Each internal angle is 90 degrees
    • Diagonals divide each other equally
    • Diagonals are not perpendicular each other
    • Diagonals bisect the opposite angles
    • It has two symmetrical axese : Bisectors of opposite sides
    • Opposite sides are parallel

    Go to Begin

    GE 06 04. Parallelogram : Properties
    • Opposite sides are parallel and equal and the sides are a, b, a, b
    • The area is a*h and h is the distance between two opposite sides
    • Each internal angle is not 90 degrees. But the opposite angles are equal
    • Ten neighbour angles are supplementary
    • Diagonals divide other diagonals equally
    • Diagonals are not perpendicular each other
    • Diagonals do not bisect the opposite angles
    • It has no symmetrical axese
    • Opposite sides are parallel

    Go to Begin

    GE 06 05. Rhombus : Properties
    • Four sides are equal and the sides are a, a, a, a
    • The area is diagonal times diagonal
    • Each internal angle is not 90 degrees. But the opposite angles are equal
    • The neighbour angles are supplementary
    • Diagonals
      • Diagonals bisect other diagonal
      • Diagonals are perpendicular each other
      • Diagonals bisect the opposite angles
    • It has two symmetrical axese : Two diagonals
    • Opposite sides are parallel
    Home work
    • Compare the square with rhombus

    Go to Begin

    GE 06 06. Change quadrilateral to equal area triangle

    Method and proof
    • Constuction
      • a. Draw a quadrilateral ABCD
      • b. Draw line DE parallel to AC
      • c. Produce BC and meet DE at P
      • d. Draw triangle ABP
      • e. Area ABP = Area ABCD
    • proof
      • a. Since DP parallel to AC
      • b. Hence area APC = area ADC
      • c. Area ABP = area APC + Area ABC = area ADC + area ABC = area ABCD

    Go to Begin

    GE 06 07. Answer


    Go to Begin

    GE 06 08. Answer

    Go to Begin

    GE 06 09. Answer

    Go to Begin

    GE 06 10. Example : Change square to equal area triangle

    Construction
    • Draw a square ABCD
    • Join diagonal AC
    • Draw line DQ parallel to AC
    • Produce BC to meet DQ at P
    • Join AP
    • Then Area of square ABCD = area of triangle ABP
    Prove that area ABCD = area ABP
    • Area ABCD = area ABC + area ACD
    • Area ABP = area ABC + area ACP
    • Triangle ACD and ACP have same base and same height. Hence area ACD = ACP
    • Hence area ABCD = area ABP

    Go to Begin

    GE 06 11. Example : Change quadrilateral to equal area triangle

    Construction
    • Draw a quadrilateral ABCD
    • Join diagonal AC
    • Draw line DQ parallel to AC
    • Produce BC to meet DQ at P
    • Join AP
    • Then Area of quadrilateral ABCD = area of triangle ABP
    Prove that area ABCD = area ABP
    • Area ABCD = area ABC + area ACD
    • Area ABP = area ABC + area ACP
    • Triangle ACD and ACP have same base and same height. Hence area ACD = ACP
    • Hence area ABCD = area ABP

    Go to Begin

    GE 06 00. Outlines

    Properties
    • Properties of rhombus
    Construction
    • Quadrilateral is changed to equal area triangle
    • Square is changed to equal area triangle

    Go to Begin

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