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Symbol Defintion
Example : Sqr(x) = Square root of x
Q01. Locus in parallelogram
Question
- Parallelogram ABCD
- AD and BC are fixed length
- Bisectors of angle BCD and angle ADC meet at O
- Find locus of O
- Angle ADC + angle BCD = 180 degrees
- Hence angle CDF + angle ECD = 90 degrees
- Hence angle EOF = angle DOC = 90 degrees
- Triangle ADF
- Angle ADF = angle AFD
- Hence AF = AD = fixed length
- Hence F is fixed point
- Triangle EBC
- Angle BEC = angle ACE
- Hence BE = BC = fixed length
- Hence E is fixed point
- Since E and F are fixed and angle EOF = 90
- Hence locus of O is a circle with EF as diameter
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Graphs in Geometry
GE 21 40
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Q02.
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Q03. New
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Q04. New
1.
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Q05. Laws in algebra
- 1. Laws of exponent : It is in Lesson 06 05
- 2. Laws of logarithm : It is in Lesson 09 02
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Q06. New
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Q07. Answer
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Q08. Answer
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Q09. Answer
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Q10. Answer
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