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Mathematics Dictionary
Dr. K. G. Shih

Centroid : Gravity cneter
Subjects


  • GE 14 00 | - Outline
  • GE 14 01 | - What is centroid ?
  • GE 14 02 | - Prove that medians of triangle are concurrent
  • GE 14 03 | - Centroid to vetex is 2/3 of it median
  • GE 14 04 | - Locus of centroid
  • GE 14 05 | - Using coordinate geometry Prove that meidians concurrent
  • GE 14 06 | - Construct triangle if 3 medians are given
  • GE 14 07 | -
  • GE 14 08 | -
  • GE 14 09 | -
  • GE 14 10 | -

  • Answers


    GE 14 01. What is centroid

    Definition
    • Medians of triangle are concurrent at a point G which is called centroid
    • Centroid is also called gravity center of a triangle
    What is concurrent ?
    • Three lines meet at one point is called concurrent
    What is median ?
    • Vertex of triangle to mid point of opposite side is called median
    • AD, BE, CF are medians of triangle as shown in diagram
    diagram

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    GE 14 02. Medians of triangle are concurrent

    diagram
    Construction
    • Draw triangle ABC
    • Let D be mid point of BC, E be midpoint of CA
    • Draw medians AD and BE intersecting at G
    • Join C and G. Produce CG to F on AB
    • Produce CF to H and let FH = CG
    • We want to prove that F is mid point of AB
    Proof
    • In triangle CAH E and G are mid points of CA and CH
    • Hence EG parallel to AH (mid point theory)
    • In triangle CBH D and G are mid points of BC and CH
    • Hence DG parallel to BH
    • Hence AGBH is a parallelogram (opposite sides parallel)
    • Hence AF = BF (properties of parallelogram)
    • Hence F is mid point and CF is medain passing G

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    GE 14 03. Centroid to vertex is 2/3 of median

    • In Q02, FH = FG (properties of parallelogram)
    • Hence FG = GH/2 = CG/2
    • CF = CG + FG = CG + CG/2 = 3*CG/2
    • Or CG = 2*CG/3 where CG is the median

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    Q04. Locus of centroid

    diagram
    Conditions
    • Let A and B are fixed and C is moving with angle ACB = constant
    • Find locus of centroid
    Diagram
    Proof
    • Draw GP parallel to CA and P on AB
    • Draw GQ parallel to BC and Q on AB
    • Hence angle PGQ = angle ACB (fixed)
    • Since GP parallel to CA hence AP = 2*AF/3
    • Since GQ parallel to BC hence BQ = 2*BF/3
    • AB is fixed and then AF and BF are fixed
    • Hence P and Q are fixed points.
    • Also PGQ is fixed angle.
    • Hence locus of G is an arc of circle passing P, G, Q.

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    GE 14 05. Coordinate geometry Prove that medians of triangle concurrent

    Reference

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    GE 14 06. Construct triangle if 3 medians are given

    • See GE 03 12

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    GE 14 07. Answer

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    GE 14 08. Answer

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    GE 14 09. Answer

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    GE 14 10. Answer

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    GE 14 00. Outline

    • Centroid : medians are concurrent
    • Two third rule : Centroid to vertex is 2/3 of it median

    Go to Begin

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