Mathematics Dictionary
Dr. K. G. Shih
Questions and Answers
Questions
Symbol Defintion
Example : x^2 = square of x
Q01 #020703 |
- What is Pythagorean triples ? Please give examples.
Q02 #020704 |
- What is abundunt number ?
Q03 #020822 |
- What is amicable number pairs ?
Q04 #020823 |
- What is perfect number ?
Q05 #020824 |
- How to find Fibonacci's sequence in Pascal Triangle ?
Q06 #021031 |
- Solve x^7 + x^6 -5*x^5 - 13*x^4 - 13*x^3 - 5*x^2 + x + 1 = 0
Q07 #030602 |
- Use diagram to find relation of doamins and signs of y, y', y"
Q08 |
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Q09 |
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Q10 |
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Answers
Q01. #020703 : Pythagorean triples
Pythagorean triples are 3 numbers satisfying the Pythagorean Law.
Example 1
3, 4, 5 are Pythagorean numbers. Since 5^2 = 3^2 + 4^2.
Multiples of these numbers are also Pythagorean numbers.
Example 2
5, 12, 13 are Pythagorean numbers.
Multiples of these numbers are also Pythagorean numbers.
Example 3
8, 15, 17 are Pythagorean numbers.
Multiples of these numbers are also Pythagorean numbers.
Reference : MD2002 11 19.
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Q02. #020704 : Abundunt numbers
Sum of the factors of a number is greater than the number itself.
The number is called abundunt number.
Note : The sum is not included the number itself.
Example 1 : Prove that 30 is abundunt number.
facors of 30 : 1, 2, 3, 5, 6, 10, 15.
Sum of factors = 1 + 2 + 3 + 5 + 6 + 10 + 15 = 42.
Example 2 : Prove that 29 is not abundunt number.
facors of 29 : 1.
Sum of factors = 1.
Hence number 29 is a deficient number and it is also a prime number.
Example 3 : Prove that 28 is not abundunt number.
facors of 28 : 1, 2, 4, 7, 14.
Sum of factors = 1 + 2 + 4 + 7 + 14 = 28.
Hence 28 is not abundunt number and it is also a perfect number.
Example 4 : Prove that 27 is deficient number.
Factors of 27 : 1, 3, 9
Sum of factors = 1 + 3 + 9 = 13.
Hence 27 is a deficient number.
Reference : MD2002 01 14.
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Q03. #020822 Amicable number pairs
Study subject
Who discovered the amicable pairs ?
Study subject
What is amicable number pairs ?
Exercise : Prove that 220 and 284 are amicable number pairs.
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Q04. #020823 What is perfect number ?
Study subject
What is perfect number ?
Exercise 1 : Prove that 6 is the first perfect number.
Exercise 2 : Prove that 28 is the second perfect number.
Exercise 3 : How to find the 3rd perfect number ?
Exercise 4 : How to find the 4rd perfect number ?
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Q05. How to find Fibonacci's sequence in Pascal Triangle ?
Study subject
Fibonacci's sequence
Recursion formula
T(0) = 0 and T(1) = 1.
T(k) = T(k-2) + T(k-1) for k > 1.
The sequence : 1, 1, 2, 3, 5, 8, 13, ......
Find T(8) = 1 + 6 + 10 + 4 = 21 in Pascal triangle as shown in diagram.
Demo are given in MD2002 program 04 07.
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Q06. Solve x^7 + x^6 -5*x^5 - 13*x^4 - 13*x^3 - 5*x^2 + x + 1 = 0
Hint
It is not easy to find the answer.
Unless we know (x+1) and (x^2+x+1) are factor of the equation
Solutions
Study subject
Equations : 11 16
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Q07. How to find signs of y, y' and y" using diagram ?
Find zeros of y, y' and y"
1. y' is zero if there is maximum or minimum point
2. y" is zero if there is a point of reflexiom
Find signs of y, y' and y"
1. If the curve is in 1st or 2nd quadrant, then y has postive sign
2. If the curve is in 3rd or 4th quadrant, then y has negative sign
3. If the curve is increasing, then y' has positive sign
4. If the curve is decreasing, then y' has negative sign
5. If the curve is cocave upward, then y" has positive sign
6. If the curve is cocave downward, then y" has negative sign
Examples to get diagra
Study subject
Diagram polynomial function in 01 01
Select section 01
Enter the application program
Select run at current location (no download)
Select yes to run
Select quartic function
Click menu
Select 01 in upper box
Click Demo command
Click 04 in lower box
Now we have a diagram of quartic function y = x^4 + x^3 - 4*x^2 + x + 1
Estimate the zeros of y, y' and y" and write down the domains
Estimate the signs of y, y' and y" and write down the domains
zeors and signs of y = x^4 + x^3 - 4*x^2 + x + 1, y' and y"
zeros of y
x = -2.7
x = -0.4
x = +1.1
zeros of y'
Minimum at x = -1.9
Maximum at x = +0.1
zeros of y" : None
Signs of y
y is positive when x = -infinit to x = -1.9
y is positive when x = -0.4 to x = +infinite
y is negative when x = -2.7 to x = -0.4
Sign of y'
y' is negative when x = -infinite to x = -1.9
y' is positive when x = -1.9 to x = 1.1
y' is negative when x = +0.1 to x = -1.9
y' is positive when x GT 1.1
Sign of y"
y" is positive when x = -infinite to x = -0.4
y" is negative when x = -0.4 to x = +1.1
y" is positive when x GT 1.1
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Q08. Answer
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Q09. Answer
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Q10. Answer
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